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Mainly because it doesn't make mathematical sense. Consider a vertical cliff (the problem is not really related to cycling) of say 1km. Person A: climbs up and down in 4 hours total Average 2km/4hours = 0.5km/h Person B: climbs up in 10 hours carrying a parachute and down in 36 seconds. Average (0.1km/h + 100km/h)/2 = 50km/h It doesn't make any sense ...


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You can. But to make the calculus work nicely, you need to invert it: Consider Is = 1 / s where s is speed in meter per second. If you go 100m @ 10m.s-1 and 100m @ 5m.s-1, you mean speed is sum(d) / sum(t / d) for each segment, or 6.7m.s-1 But your Is is sum(d * Is) / sum(d), or sum(d / s) / sum(d) Which is 1.5s.m-1, or (.1 + .2) / 2 So as soon as you ...


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Your speed over flat ground seems more important to me. Or you want to ignore outliers, correct? The median is remarkably suited for that. Why not collect speed values and then compute the median? The two methods, collecting the speeds via time or distance are just different sampling methods to estimate the distribution of speeds. One may give a better ...



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