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Jul 14, 2018 at 8:14 comment added cmaster - reinstate monica Caliper breaks have the same problems with overheating as internal hub breaks: Put too much heat into the tire, and it'll fail. Yes, they have more dissipation area, but the tire cannot withstand the same temperatures that an internal hub break can. So, if you need a descent enduring break, best go for disk breaks. They can handle much higher temperatures than rim breaks, and they are much better at dissipating energy than internal break.
Mar 13, 2016 at 21:04 comment added Craig Hicks Alan - The determining factor in going end-over is braking torque at the axle. The braking axle torque at which end-over occurs is the same regardless of the braking system.
Jun 9, 2015 at 20:38 comment added ALAN WARD Sorry, LopSae, cannot agree with you. When you brake, your tire is applying a certain force to the ground - and, conversely, the ground is applying an equal and opposing force to the wheel. If you use caliper brakes, the brakes are applying another force, also to the wheel, but not at the same point. It is being applied approximately one diameter up. This creates a torque, which depends not only on the forces applied, but also on the distance between points of application. Applying the same braking force much closer to the hub, as in disk brakes, means the distance is halved ... as is torque.
Jun 9, 2015 at 20:32 comment added Maic López Sáenz The drawback you mention on the third paragraph of caliper brakes is that dirt can get more easily in the surface and prevent braking, while dirt track bikes use disk brakes because the disk (the braking surface) is father away from all the dirt. Going over the handlebars has more to do with braking power, and any good braking system will be powerful enough to cause that.
Jun 8, 2015 at 10:26 comment added aSemy Thanks for your answer! I'll stick with discs. It's a shame hub brakes aren't up for it.
Jun 3, 2015 at 19:18 review First posts
Jun 3, 2015 at 22:27
Jun 3, 2015 at 19:08 history answered ALAN WARD CC BY-SA 3.0