Timeline for How do I calculate the power required to climb a hill at a given cadence?
Current License: CC BY-SA 3.0
22 events
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| Sep 20, 2019 at 20:30 | comment | added | SurpriseDog | That depends on you the rider, the bike and any number of factors. Try using this calculator here: bikecalculator.com | |
| Jul 16, 2019 at 19:33 | answer | added | Duc | timeline score: 1 | |
| Mar 27, 2018 at 9:30 | history | edited | Criggie♦ |
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| S Jun 16, 2012 at 5:16 | history | suggested | amcnabb | CC BY-SA 3.0 |
Clarify the title and clarify grammar
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| Jun 15, 2012 at 21:18 | review | Suggested edits | |||
| S Jun 16, 2012 at 5:16 | |||||
| Jan 25, 2012 at 3:05 | vote | accept | Rick Ant | ||
| Jan 24, 2012 at 14:52 | comment | added | R. Chung | Right, so a watt is a joule/sec. So, if you had a very good estimate of food calories (= kilocalories) spent, you could use the "rule of thumb conversion" to say that was equivalent to the number of kilojoules spent, and divide by the time elapsed in seconds to get average power in watts. In practice, good estimates of Calories spent are hard to come by but, especially on a bicycle, one can occasionally get a good estimate of power (such as for hill climbs). This gives a good estimate of kilojoules and you can then convert that into food calories spent. | |
| Jan 24, 2012 at 4:11 | comment | added | Daniel R Hicks | And a joule is one watt*second. | |
| Jan 24, 2012 at 3:55 | comment | added | R. Chung | Rick: Yes, but you also need to account for your gross metabolic efficiency in converting between calories burnt and power. In general, GME ranges between about 20% and 25%. As it happens, 1 calorie = 4.184 joules, or 1 joule = .239 calories, so a common rule of thumb is to assume a GME of 23.9%, in which case the number of food calories (= Calorie, = 1000 calories = 1 kilocalorie) is roughly equivalent to 1 kilojoule. Typically it's easier to estimate work in joules (or kilojoules) than it is to estimate Calorie expenditure so the conversion is usually in the opposite direction: power -> Cal. | |
| Jan 24, 2012 at 3:10 | comment | added | Rick Ant | can I calculate power from calories I burned divide by time I spent ? | |
| Jan 24, 2012 at 0:45 | answer | added | imel96 | timeline score: 0 | |
| Jan 23, 2012 at 18:47 | answer | added | R. Chung | timeline score: 15 | |
| Jan 21, 2012 at 8:25 | history | tweeted | twitter.com/#!/StackBicycles/status/160639059679653889 | ||
| Jan 20, 2012 at 12:36 | comment | added | Daniel R Hicks | Attach torque wrenches in place of your crank arms and read them out several times a revolution. (Which is to say that that's the hard problem.) | |
| Jan 20, 2012 at 9:30 | answer | added | tdc | timeline score: 5 | |
| Jan 20, 2012 at 5:45 | comment | added | Rick Ant | How can I know my torque ? | |
| Jan 20, 2012 at 5:19 | vote | accept | Rick Ant | ||
| Jan 25, 2012 at 3:05 | |||||
| Jan 20, 2012 at 4:08 | comment | added | Daniel R Hicks | You need to know what torque is being applied, in addition to the RPM. Or you could simply calculate the power required to climb a given grade at a given speed. (Personally, on a 10% hill, I'm just thankful to be able to keep moving.) | |
| Jan 20, 2012 at 4:07 | history | edited | heltonbiker |
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| Jan 20, 2012 at 4:07 | history | edited | heltonbiker |
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| Jan 20, 2012 at 4:04 | answer | added | heltonbiker | timeline score: 3 | |
| Jan 20, 2012 at 2:45 | history | asked | Rick Ant | CC BY-SA 3.0 |