i'm considering a machine build based on MTB hydraulic lever brake and I would like to know if the lever, pushed by hand, will handle 13 bars /190 PSI ? I'm really new to this kind of measurement.
asuming 300 N as average grip multiplied by a leverage ratio of 10 it is 3000 N of axial force. the piston diameter is about 10 mm so the piston effective area will be 0.785 squared mm. so the presure could be 3000 N/ .785 cm2 = 3821.7 N/cm2 equal to 5542 PSI. so it can handle almost 30 times what you need. the problem is: lack of power if you can only apply 190 PSI maybe the brakes wont work at all.