3

What's the cone spanner size for cone nut on Shimano WH-R550 Front wheel ? Is it 17mm or 18mm ? I tried with 16, it seems, need more, 1 or 2mm bigger.

Thanks

3
  • "I tried with 16, it seems, need more, 1 or 2mm bigger." You answered your own question.
    – cmannett85
    Feb 15, 2012 at 10:57
  • My experience has been that it's generally a step smaller than the lock nut. Feb 15, 2012 at 11:59
  • I have an idea, clamp 2 tire opener with variable spanner, hopefully my tire opener is thin enouh ( alumunium one)
    – Rick Ant
    Feb 16, 2012 at 6:17

2 Answers 2

2

17mm/15mm is usual for Shimano cones.

0

EDIT: I took a late look at some pictures of the wheel you mentioned (Shimano WH-R550). It looks quite different from the regular mtb shimano hubs, so please consider the following answer as applying to regular mountain-bike shimano hubs.


From my experience with shimano hubs, there are two parts:

  1. The locknut, which face outwards and make contact with the fork/frame, is usually 17mm. Since you need to tighten it with the other side fixed, you can use a 17mm wrench at one side and a 18mm wrench at the other if you don't want to have two (big/expensive) 17mm wrenches.
  2. Cones are just inside the locknuts and might be 13 or 14, or even different. Usually you need a dedicated cone wrench since normal wrenches are too thick to fit in the narrow fitting in the cone.

Some shimano models have a double-size cone, to allow use of two wrenches of different sizes, so it helps folks who have only one size of cone wrench (Shimano is rarely so considerate).

I waited (and suffered) too much before buying my cone wrenches. If I knew how much a difference they make, I'd have bought them at the same time I bought the bike!

1
  • locknut is equal to 18mm, cone nut can be 17mm, i bought one for 17mm and 18mm cone wrench, since 16mm doesn't fit and I can not use variable wrench i have, too thick, i wish i have a thin plier (2mm alligator) it will work....for holding when i loosen or tighten the lock nut..
    – Rick Ant
    Feb 16, 2012 at 2:34

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.