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Nov 30, 2020 at 16:43 comment added Chris H My reading so far disagrees with that assumption - the circuits I've seen use the MOSFET(s) in linear mode, not fully on, i.e. they're acting as controlled resistors. But we've got too far from my original simple suggestion for me to have much more to offer. Your latest edit says you're an EE - you're probably more qualified than most of us here to address this question
Nov 30, 2020 at 16:37 comment added joedarock Since the resistance of the windings is likely to be higher than the on-resistance of the fets, most of the heat will be generated there (assuming a short-circuit load). Still, all this is academic and we could,go on forever about it. Has anyone actually done it and what was the outcome?
Nov 29, 2020 at 15:24 comment added Chris H @joedarock MOSFET braking circuits don't (always) need load resistors, but dump a lot of heat in the MOSFETs themselves, meaning big heatsinks as well as big MOSFETs sized for peak current and average braking power, which could be a couple of hundred Watts. The resistors were for a simple on/off setup instead.
Nov 29, 2020 at 15:15 comment added joedarock Seems to me you don't need a lead resistor. A PWM controlled short circuit could control average load current and therefore braking strength. Of course, the PWM MOSFETS have to be sized to withstand the peak currents.
Nov 29, 2020 at 8:36 history edited Chris H CC BY-SA 4.0
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Nov 29, 2020 at 8:22 history answered Chris H CC BY-SA 4.0